Assertion : Aniline does not undergo Friedel- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Aniline is a Lewis base due to the lone pair of electrons on the nitrogen atom of the $-NH_2$ group.Friedel-Crafts reaction requires $AlCl_3$ as a

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) Aniline is a Lewis base due to the lone pair of electrons on the nitrogen atom of the $-NH_2$ group.Friedel-Crafts reaction requires $AlCl_3$ as a Lewis acid catalyst.When aniline reacts with $AlCl_3$,it forms a salt (an acid-base adduct) where the nitrogen atom coordinates with the aluminum atom.This results in the nitrogen atom acquiring a positive charge,which acts as a strong deactivating group for the benzene ring,thereby inhibiting the electrophilic substitution reaction required for Friedel-Crafts alkylation or acylation.Therefore,both the Assertion and the Reason are correct,and the Reason is the correct explanation for the Assertion.

Assertion : Aniline does not undergo Friedel-Crafts reaction.
Reason : $-NH_2$ group of aniline reacts with $AlCl_3$ (Lewis acid) to give acid-base reaction.

Similar Questions

How will you carry out the following conversion: Benzene to $p$-nitroaniline?

The product of the mustard oil reaction is:

Which of the following compounds will have the highest $pK_b$ value?

Primary nitroalkanes on boiling with hydrochloric acid undergo hydrolysis to form

$C_6H_5CH_2Cl$ $\xrightarrow{\text{Alc. } NH_3} A$ $\xrightarrow{2 CH_3Cl} B$. The product $B$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Aniline does not undergo Friedel-Crafts reaction.Reason : $-NH_2$ group of aniline reacts with $AlCl_3$ (Lewis acid) to give acid-base reaction.